Effective Resistance of a circuit

Click For Summary
SUMMARY

The effective resistance of the given circuit is calculated as 22.5Ω, using both right-to-left and left-to-right approaches. The calculations involve combining resistances in series and parallel configurations, specifically using the formulas for series resistance (R = R1 + R2) and parallel resistance (Rp = R1 R2 / (R1 + R2)). The confusion arises from incorrectly assuming that the 18Ω and 6Ω resistors are in series when they are actually in parallel, leading to incorrect results when calculated from left to right.

PREREQUISITES
  • Understanding of series and parallel resistor configurations
  • Familiarity with Ohm's Law
  • Ability to perform basic arithmetic operations with resistances
  • Knowledge of circuit diagram interpretation
NEXT STEPS
  • Study the principles of series and parallel circuits in detail
  • Learn about Kirchhoff's laws for circuit analysis
  • Explore circuit simulation tools like LTspice for practical applications
  • Review advanced topics in circuit theory, such as Thevenin's and Norton's theorems
USEFUL FOR

Students studying electrical engineering, hobbyists building circuits, and anyone looking to deepen their understanding of circuit resistance calculations.

logearav
Messages
329
Reaction score
0

Homework Statement



Revered members,
I need to find the effective resistance of this circuit which i have given in attachment.
circuit.

Homework Equations


The Attempt at a Solution


Now let me explain how i carried out.
I proceeded from right to left
1) R s = 12 + 6 = 18Ω
2) Rp = R1 R2/R1 + R2 which is (18 x 6)/24 = 4.5Ω
3) R = R1 + R2 = 18 + 4.5 = 22.5Ω
I have given the above steps in my second attachment
Now, for the same problem when i proceed from left to right
1) I took 18Ω and 6Ω as parallel i got 4.5 Ω and then this 4.5 is in series with
12 Ω and 6Ω so 4.5 + 12 + 6 = 22.5Ω
I have given the above steps in my third attachment
Now my question is why should not i take 18 Ω and 6Ω as series connection and proceed, because when i take those 18 Ω and 6Ω as described in my last attachment in the following reply,
i get wrong answer. Where do i go wrong?

Homework Statement


Homework Equations


The Attempt at a Solution

 

Attachments

  • prob.png
    prob.png
    4.8 KB · Views: 583
  • IMG_0001.jpg
    IMG_0001.jpg
    5.8 KB · Views: 548
  • IMG.jpg
    IMG.jpg
    10.4 KB · Views: 549
Physics news on Phys.org
continuing my previous query, this is my last attachment. Is this not a series circuit? But when i take this as series and proceed from left to right, i get wrong answer.
 

Attachments

  • picture.jpg
    picture.jpg
    4.3 KB · Views: 503
why should not i take 18 Ω and 6Ω as series connection and proceed?
Because, in the first image, they are not in series. You were correct in proceeding from right to left (2nd image).
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 27 ·
Replies
27
Views
5K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
5
Views
2K
Replies
9
Views
2K