Efficient Computation of Convolution using Z-Transform in Discrete-Time Signals

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The discussion focuses on the efficient computation of convolution using Z-transforms for discrete-time signals, specifically for the signals x_1(n) and x_2(n). The Z-transforms are derived as X_1(z) and X_2(z), leading to the combined output Y(z) through multiplication. Participants suggest using LaTeX for clearer presentation of mathematical expressions and recommend the use of square brackets for discrete-time signals. Additionally, it is clarified that z is a continuous variable while n is discrete. The conversation emphasizes the importance of proper notation for clarity in signal processing discussions.
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x_1(n) = (!/4)^n u(n-1) and x_2(n) = [1- (1/2)^n] u(n)

X_1(z) = (1/4)z^-1 / (1-(!/4)z^-1 and X_2(z) = 1/(1-z^-1) + 1/(1-(1/2)z^-1)

Y(z) = X_1(z) X_2(z) = (-4/3) /(1-(1/4)z^-1 + (1/3) / (1-z^-1) + 1/(1-(1/2)z^-1
 
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may i suggest that you try using the \LaTeX pasteup provided by physicsforums? it makes it much easier to read. also try to use the convention of square brackets (instead of parenths) for discrete-time or discrete-frequency signals. like

x[n] = \frac{1}{N} \sum_{k=0}^{N-1} X[k] e^{j 2 \pi k n / N}

as opposed to

x(t) = \int_{-\infty}^{+\infty} X(f) e^{j 2 \pi f t} df

z is a continuous variable, BTW. but n is discrete.
 
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