Efficiently Solve a Challenging Rotation Problem | Homework with Shell Method

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 3K views
iRaid
Messages
558
Reaction score
8

Homework Statement


serocp.png



Homework Equations


Shell method


The Attempt at a Solution


Not sure if this is right, but the integral I set up is:
[tex]2\pi \int_0^1 (4-y)(\sqrt{siny})dy[/tex]


Finding the radius is my big problem with these problems, I can't visualize it very well.

Any help is appreciated.
 
Physics news on Phys.org
iRaid said:

Homework Statement


serocp.png


Homework Equations


Shell method

The Attempt at a Solution


Not sure if this is right, but the integral I set up is:
[tex]2\pi \int_0^1 (4-y)(\sqrt{siny})dy[/tex]
Finding the radius is my big problem with these problems, I can't visualize it very well.

Any help is appreciated.
That looks fine except for the limits of integration.

How did you get those limits?
 
graphing [tex]\sqrt{siny}[/tex] from 0 to pi gives me a curve that goes to 1 and back to 0. Since I'm integrating wrt y, I figured it's 0 to 1?
 
Last edited:
iRaid said:
graphing [tex]\sqrt{siny}[/tex] from 0 to pi gives me a curve that goes to 1 and back to 0. Since I'm integrating wrt y, I figured it's 0 to 1?
You don't have [itex]\ \ y=\sqrt{\sin(x)}\ \[/itex] with x going from 0 to π.

You have [itex]\ \ x=\sqrt{\sin(y)}\ \[/itex] with y going from 0 to π --- and your integration is w.r.t. y.
 
SammyS said:
You don't have [itex]\ \ y=\sqrt{\sin(x)}\ \[/itex] with x going from 0 to π.

You have [itex]\ \ x=\sqrt{\sin(y)}\ \[/itex] with y going from 0 to π --- and your integration is w.r.t. y.


Thanks, probably shouldn't agree with wolfram straight after I graph...