- #1
shehry1
- 44
- 0
For a hermitian operator A, does the function f(A) have the same eigenkets as A?
This has been bothering me as I try to solve Sakurai question (1.27, part a). Some of my class fellows decided that it was so and it greatly simplifies the equations and it helps in the next part too but I don't think so because I might add anything to A in order to make it non-hermitian.
This has been bothering me as I try to solve Sakurai question (1.27, part a). Some of my class fellows decided that it was so and it greatly simplifies the equations and it helps in the next part too but I don't think so because I might add anything to A in order to make it non-hermitian.