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How to prove that eigenvalue of lowering operator is zero?

- Thread starter izzmach
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How to prove that eigenvalue of lowering operator is zero?

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ShayanJ

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For other eigenvectors of the lowering operator(coherent states), eigenvalues are non-zero.

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lowering operator.

It is easy to consider the H.OSc. and operate with the lowering operator till it gets to the min = h-bar omega/2 and if you apply furthe the lowering operator then you get zero. Of course the system maybe different in different situation and hence the minimum state may vary.

watch out that minimum state or the vacuum state is not the zero state, a zero state does not exists in nature.

The proof is kind of trival. google on Fock space and there you get your proof.

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radium

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If you are talking about an eigenvalue of the lowering operator you must consider coherent states which are constructed to be eigenstates of the annihilation operator. The eigenvalue is some complex number. Coherent states are used in path integrals. If you look at the coherent states in the harmonic oscillator, they behave the most classically in terms of minimized uncertainty.

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