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Well, the vector Laplacian of the gravitational field (one possible meaning of "the second d") is in fact 0 outside a point mass. However, since there are three dimensions there are an infinite number of possible second derivatives of the gravitational field. I don't know which one you are specifically referring to as "the second d", but you are correct that many of the possible second derivatives (besides the Laplacian) may be non-zero in vacuum.Mueiz said:The second d of gravitational field does not equal zero outside
For a point mass, yes. What is the density of a point mass?Mueiz said:The lablacian of the potential equals zero outside and undefined at the origin
Why don't you answer this question yourself by doing the following exercise. Start with the known expression for the gravitational potential inside a solid uniform spherical mass (i.e. a solid ball, not a hollow shell) of unit density (http://en.wikipedia.org/wiki/Gravitational_potential#Spherical_symmetry), take the Laplacian of that expression and see what you get. And yes, I can do this exercise but then how will you learn.Mueiz said:If poission equation relates Lablacian of Potential which is always zero why not just write it ; L(potential of GF)=zero ?
I don't know how you come up with any of this. This whole paragraph is simply incorrect. Please do the exercise above to see for yourself.Mueiz said:the only thing it say is that; outside the source
the lablacian of the potential equals zero and it cannot be applied in the presence of matter ,(in both cases there is no method to characterize the differences in gravitational properties and relate it quantitatively to matterial properties
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