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Homework Statement
This is exercise 2.4.2 from Pringle and King, Astrophysical Flows (CUP 2007):
Along an infinite, straight, one-track road the local density of cars is \rho(x,t) and the local velocity of cars (all assumed to be traveling in the same direction) is v(x,t). Discuss why it might be reasonable to assume that v is solely a function of \rho.
Making this assumption, show that <br /> \frac{\partial \rho}{\partial t} + c(\rho) \frac{\partial \rho}{\partial x} = 0<br /> where the kinematic wave speed is defined by c(\rho) = Q'(\rho) and Q = \rho v is the local flux of cars.
Traffic flow along a particular highway can be fitted approximately for \rho < \rho_{\mathrm{max}} by Q(\rho) = V_0\rho \log(\rho_{\mathrm{max}}/\rho), where V_0 = 25\,\mathrm{kph} and \rho_{\mathrm{max}} = 150\,\mathrm{vechicles}\,\mathrm{km}^{-1}.
Show that information propagates upstream at a speed V_0 relative to the local vehicle velocity.
Show that there is a maximum traffic flow which occurs at some density \rho_{\mathrm{crit}} corresponding to a critical speed v_{\mathrm{crit}} of around 75 kph.
[Remainder omitted]
Homework Equations
The Attempt at a Solution
All is straightforward until we consider the particular choice of Q. Firstly we have <br /> c = Q' = V_0\left(\log(\rho_{\mathrm{max}}/\rho) - 1\right) = \frac Q\rho - V_0 = v - V_0 so indeed c - v = -V_0.
Now we're asked to find the maximum traffic flow. This corresponds to the maximum of Q, and we've just shown that Q' = v - V_0. Thus the maximum occurs at v_{\mathrm{crit}} = V_0, at which point \rho_{\mathrm{crit}} = e^{-1}\rho_{\mathrm{max}}.
According to the question, v_{\mathrm{crit}} \approx 3V_0. Am I missing something obvious, or is the question wrong?