Elastic Collision: Momentum or Energy?

AI Thread Summary
Elastic collisions are defined by the conservation of kinetic energy, not momentum, which is conserved in all types of collisions. In a recent lab, participants mistakenly identified a collision as elastic based solely on momentum conservation, neglecting to verify energy conservation. It was pointed out that the lab did require checking energy, which was not conserved in their case. An elastic collision maintains the internal energy of the colliding objects, including both translational and rotational energy. For further understanding, exploring Newton's Law of Restitution is recommended for insights into inelastic collisions.
Physics is Phun
Messages
100
Reaction score
0
Is elastic collision defined as a collision where no energy is lost or where no momentum is lost? We had to do a lab in class and one question was whether the collison was elastic. I think we all got it wrong because we sayed it was elastic because momentum was conserved. But we were supposed to check if energy was (apparently it wasn't) conserved. (It seems kind of stupid because nowhere in the lab did we have to find the energy so we would have to find it separately to find whether it was elastic or not.) So is elasticity defined by momentum or energy?
 
Physics news on Phys.org
An elastic collision is one in which the kinetic energy is conserved. Momentum is conserved in any collision, whether elastic or inelastic.
 
An elastic collision is one in which the internal energy of the colliding objects remains unchanged meaning that the translational plus rotational energy of both objects is conserved.

Also, you were in fact asked in the lab to find the energy when the question of whether the collision is elastic was raised. :-)
 
If you want to know more about inelastic collision, I suggest you look up on Newton's Law of Restitution.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?

Similar threads

Replies
53
Views
4K
Replies
10
Views
3K
Replies
4
Views
1K
Replies
41
Views
2K
Replies
10
Views
4K
Replies
4
Views
2K
Back
Top