Elastic Collision using Special Relativity

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SUMMARY

The discussion focuses on solving a problem related to perfectly elastic collisions in the context of special relativity. The scenario involves two identical particles, one with a kinetic energy ten times its rest mass energy, and the other at rest. The participant attempts to use the center of mass frame transformation and conservation laws to determine the final kinetic energies and deflection angles post-collision. Key equations referenced include the kinetic energy formula KE=mc²(γ - 1) and the relationships involving Lorentz factors γ and β.

PREREQUISITES
  • Understanding of special relativity concepts, particularly Lorentz transformations.
  • Familiarity with kinetic energy calculations in relativistic contexts.
  • Knowledge of conservation of momentum and energy principles.
  • Ability to perform transformations to the center of mass frame.
NEXT STEPS
  • Study the derivation and application of Lorentz transformations in elastic collisions.
  • Learn how to calculate kinetic energy using the formula KE=mc²(γ - 1) in various scenarios.
  • Explore examples of two-body collisions in special relativity to solidify understanding.
  • Investigate the implications of deflection angles in elastic collisions using conservation laws.
USEFUL FOR

Students and educators in physics, particularly those focusing on mechanics and special relativity, as well as anyone interested in advanced collision dynamics.

sanjewierden
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Homework Statement


I was given the following problem and I an trying to discover if it can be answered by transforming to the center of mass frame and then transforming back.

"Consider a perfectly elastic collision between a particle moving with kinetic energy 10 times its rest mass energy and an identical particle at rest. After the collision the incident particle is moving in a direction 10 degrees deflected from its original path. Find the final kinetic energies of both particles and the angle of the path of the struck particle relative to the incident direction."

The Attempt at a Solution


I started using the relationship of the rest mass energy to show
KE= ρ^2/(2m) = ((γ^2)/2)*m*v^2
so 20= (γ^2)(β^2) thus, β=sqrt(20/21) and γ=sqrt(21)

then I used conservation of momentum and conservation of momentum to try and answer the question. I tried it using a transform to the center of mass frame but I want to be sure that this is even possible. I always get confused when doing these transformations as well.
 
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Hi. Welcome to Physics Forums.

Isn't the kinetic energy given by KE=mc^2(\gamma -1), in which case γ=11?
 

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