Elastic potential energy of a spring

AI Thread Summary
The discussion focuses on calculating the elastic potential energy stored in a spring and determining the mass that causes a different extension. The elastic potential energy formula used is PE = 0.5kx^2, but the user is advised to convert units from N·cm to J (N·m) for accuracy. To find the second mass, participants suggest using a free body diagram and applying Newton's second law to analyze the forces acting on the mass. This approach will clarify the relationship between the spring force and the weight of the suspended mass. Understanding these principles is essential for solving the problem correctly.
jeunesse27
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Hello,
I'd relly appreciate some guidance on this one:

1. The length of a spring increases by 7.0 cm from its relaxed length when a mass of 1.7 kg is hanging in equilibrium from the spring. Spring constant 2.38 N/cm.
How much elastic potential energy is stored in the spring?
A different mass is suspended and the spring length increases by 12.9 cm from its relaxed length to its new equilibrium position. What is the second mass?



Homework Equations


PE=.5kx^2


The Attempt at a Solution


.5(2.38)(7)^2=58.31
 
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jeunesse27 said:
Hello,
I'd relly appreciate some guidance on this one:

1. The length of a spring increases by 7.0 cm from its relaxed length when a mass of 1.7 kg is hanging in equilibrium from the spring. Spring constant 2.38 N/cm.
How much elastic potential energy is stored in the spring?
A different mass is suspended and the spring length increases by 12.9 cm from its relaxed length to its new equilibrium position. What is the second mass?



Homework Equations


PE=.5kx^2


The Attempt at a Solution


.5(2.38)(7)^2=58.31


You must change the units for your PE calculation. Your current answer is \rm N\cdot cm, but you should write it in terms of \rm J = N\cdot m.

To figure out the unknown mass, draw a free body diagram, and then apply Newton's 2nd postulate for static equilibrium.
 
What forces are there acting on the mass? Obviously there is the spring force (up), but is there another force on the mass that's keeping the spring stretched? As dr_k said, drawing an FBD will help you sort this weighty problem out.
 
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