Electric Charge and Electric Fields

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SUMMARY

The discussion focuses on calculating the electric field generated by an infinite plane sheet with a surface charge density of 2.5 x 10^6 excess electrons per square centimeter. The electric field magnitude at a point 5 cm from the sheet is determined to be 226 N/C directed towards the sheet. The relevant equation for this calculation is E = sigma / (2 * epsilon_0), where sigma represents the surface charge density and epsilon_0 is the permittivity of free space. The distance from the sheet is deemed irrelevant due to the infinite nature of the plane.

PREREQUISITES
  • Understanding of electric fields and their properties
  • Familiarity with the concept of surface charge density
  • Knowledge of the equation E = sigma / (2 * epsilon_0)
  • Basic grasp of the charge of an electron and unit conversions (cm² to m²)
NEXT STEPS
  • Study the derivation of the electric field equation for infinite plane sheets
  • Explore the concept of surface charge density in more detail
  • Learn about the implications of electric fields in electrostatics
  • Investigate the role of permittivity of free space (epsilon_0) in electric field calculations
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding electrostatics, particularly the behavior of electric fields generated by charged surfaces.

aquabug918
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Each quare centimeter of the surface of an infinite p;ane sheet of paper has 2.5 X 10^6 excess electrons. Find the magnitude and direction of the electric field at a point 5 cm from the surface of the sheet, if the sheet is large enough to be treated as an infinite plane.

This is an odd problem and the answer is:
226 N/C towards the sheet

I understant why it is towards the sheet. I am guessing that since it is an infinite plane the 5 cm distance is unimportant.

does this have something to do with the equation: E = 2*sigma / 2*Eo

Thanks!
 
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aquabug918 said:
Each quare centimeter of the surface of an infinite p;ane sheet of paper has 2.5 X 10^6 excess electrons. Find the magnitude and direction of the electric field at a point 5 cm from the surface of the sheet, if the sheet is large enough to be treated as an infinite plane.

This is an odd problem and the answer is:
226 N/C towards the sheet

I understant why it is towards the sheet. I am guessing that since it is an infinite plane the 5 cm distance is unimportant.

does this have something to do with the equation: E =sigma / 2*Eo

Thanks!

Yes, that's the basic idea (except that the equation is 2 sigma /(2 epsilon_0).

That's all there is to it.
(you know how to calculate sigma, I assume. Just take the number of excess electrons times the charge of one electron divided by the 1 cm^2. Don't forget that 1cm^2 = 10^(-4) m^2).

EDIT: I retyped the wrong equation by mistake. Sorry. It is of course sigma/(2 epsilon_0)

Patrick
 
Last edited:
Thanks a lot, i understand it better now!
 

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