(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A charged water droplet of radius 0.02 mm remains stationary in air. If the electric field of the earth is 100 N/C downward,what is the charge on the water droplet? By comparison with its neutral state, how many electrons must the water droplet have gained or lost? [ Density of water is 103 kg m-3 ]

2. Relevant equations

E=F/q , F=ma , p=m/v

3. The attempt at a solution

I got the first answer ...which i have used

q = ma/E which mass of water droplets is derive from the density formula of a sphere and the density formula...

I dont quite understand by the second part?

"By comparison with its neutral state, how many electrons must the water droplet have gained or lost?"

what it is meant by neutral state?

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# Electric Charge of Water droplet falling

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