A battery , ammeter with resistance , 1 ohm and a resistor are connected in series .A voltmeter of 500 ohm is connected parallel to the resistor . The actual resistance of R is 100 ohm , what is the ratio of (the resistance R determined)/(the actual resistance of R) ?
The Attempt at a Solution
Let the emf of the battery be E and resistance of resistor , R
pd across R = [R/(1+R)]E
and that leads me to nowhere .