- #1

- 438

- 0

## Homework Statement

A battery , ammeter with resistance , 1 ohm and a resistor are connected in series .A voltmeter of 500 ohm is connected parallel to the resistor . The actual resistance of R is 100 ohm , what is the ratio of (the resistance R determined)/(the actual resistance of R) ?

## Homework Equations

## The Attempt at a Solution

Let the emf of the battery be E and resistance of resistor , R

pd across R = [R/(1+R)]E

I(500)= [R/(1+R)]E

and that leads me to nowhere .

Last edited: