Electric dipole in an electric field

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 5K views
vladimir69
Messages
124
Reaction score
0

Homework Statement


An electric dipole (something that has charge +q on one end and charge -q on the other end separated by a distance 2a) is in a uniform horizontal electric field of magnitude E. Initially the electric dipole is aligned horizontally until it is displaced slightly by an angle theta from the horizontal. Show that the electric dipole undergoes simple harmonic motion with frequency given by
[tex]f=\frac{1}{2\pi}\sqrt{\frac{(m_{1}+m_{2})qE}{2m_{1}m_{2}a}}[/tex]


Homework Equations


[tex]I\alpha=\tau_{net}[/tex]
[tex]\omega=2\pi f[/tex]
[tex]F=qE[/tex]
[tex]\theta(t)=A\cos(\omega t)[/tex]

The Attempt at a Solution


Here is what I got
[tex]I=(m_{1}+m_{2})a^2[/tex]
[tex](m_{1}+m_{2})a^2\frac{d^2\theta}{dt^2}\approx 2aqE\theta[/tex]
and the frequency I get pops out as
[tex]f=\frac{1}{2\pi}\sqrt{\frac{2qE}{(m_{1}+m_{2})a}}[/tex]
Can't see where I have gone wrong
 
Physics news on Phys.org
I thought the units were ok in both the equations
 
Yes, you are right, I misread the formula somehow...

The question is if the dipole rotates around a fixed axis through its centre, so both masses are at a distance "a" from the axis of rotation or it is free and then it rotates around its CM.
In case of the first situation, your formula is right. The formula given by your book is valid for the free dipole. In this case you need the moment of inertia with respect to the CM.

ehild
 
Ok I see now, thanks for your help.