Electric Field and Magnitude Problem

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SUMMARY

The discussion focuses on calculating the electric field magnitude at point P due to two identical point charges, q1 and q2, both valued at +2.5 x 10-6 C. The electric field equations used are E = k x Q / r2, where k is the Coulomb's constant. The calculated electric fields are E1 = 9 x 106 N/C from q1 and E2 = 1.563 x 106 N/C from q2. The next step involves decomposing these fields into their horizontal and vertical components to find the resultant electric field at point P.

PREREQUISITES
  • Understanding of Coulomb's Law and electric field equations
  • Familiarity with vector decomposition techniques
  • Basic knowledge of trigonometry
  • Concept of point charges in electrostatics
NEXT STEPS
  • Study vector addition in physics to combine electric fields
  • Learn about Coulomb's constant (k) and its applications
  • Explore trigonometric functions for resolving vectors
  • Investigate the principles of superposition in electric fields
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Students studying electrostatics, physics educators, and anyone seeking to understand electric field calculations involving multiple point charges.

pstir2
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Homework Statement


Two identical point charges, q1 = +2.5 x 10-6 C and q2 = +2.5 x 10-6 C, are placed as shown in the diagram below. Point P is a distance 0.05 m from q1 and 0.12 m from q2, such that the angle at P is 90 degrees. Calculate the magnitude of the Electric field E at point P.

Homework Equations


Not sure which of these rules would apply. Also I suck at vectors
F = k x q1 x q2 / r^2

E = k x Q / r^2

The Attempt at a Solution



Electric Field Magnitude.jpg

So I have created the diagram and I believe I have to use the second formula twice, along with some trigonometry, but I'm not sure.

E1 = k x Q1 / r^2
E1 = k x +2.5 x 10^-6 / 0.05^2
E1 = 9 x 10^6

E2 = k x Q2 / r^2
E2 = k x +2.5 x 10^-6 / 0.12^2
E2 = 1.563 x 10^6

I Can't do vectors at all. Please help.
 
Last edited:
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Step 1:
Decompose the E field you got at point P due to q1 to horizontal and vertical components.
Do the same for E field you got at point P due to q2.
 
pstir2 said:
So I have created the diagram and I believe I have to use the second formula twice, along with some trigonometry, but I'm not sure.
That's exactly correct.

Keep going! Find the field from each charge, then find the resultant field by adding the vectors.
 

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