Two identical point charges, q1 = +2.5 x 10-6 C and q2 = +2.5 x 10-6 C, are placed as shown in the diagram below. Point P is a distance 0.05 m from q1 and 0.12 m from q2, such that the angle at P is 90 degrees. Calculate the magnitude of the Electric field E at point P.
E = k x Q / r^2
This plus vector which I suck at.
The Attempt at a Solution
So I have created the diagram and I believe I have to use the second formula twice, along with some trigonometry, but I'm not sure.
E1 = k x Q1 / r^2
E1 = k x +2.5 x 10^-6 / 0.05^2
E1 = 9 x 10^6
E2 = k x Q2 / r^2
E2 = k x +2.5 x 10^-6 / 0.12^2
E2 = 1.563 x 10^6
I Can't do vectors at all. Please help.