# Electric Field and two point particles

• fallen186
In summary, two point particles with a total charge of 185 µC and separated by a distance of 0.4 m exert a force of 80 N on each other. The charges on each particle are calculated to be q1=8.05µC and q2=176 µC. This is consistent with the fact that the type of charge does not affect the calculation of force, as determined by the equation F=k*\frac{|q_{1}*q_{2}|}{r^{2}}. When the particles attract each other, the charges remain the same but one of them becomes negative.
fallen186

## Homework Statement

Two point particles separated by 0.4 m carry a total charge of 185 µC.
(a) If the two particles repel each other with a force of 80 N, what are the charges on each of the two particles?
q1=8.05µC
q2=176 µC
*I know they don't add up to 185 but it took both of the answers as correct*
(b) If the two particles attract each other with a force of 80 N, what are the charges on the two particles?

I don't see why it wouldn't be the same answer except one of them would be negative.
According to F=k*$$\frac{|q_{1}*q_{2}|}{r^{2}}$$The type of charge doesn't matter when calculating force.

fallen186 said:

## Homework Statement

Two point particles separated by 0.4 m carry a total charge of 185 µC.
(a) If the two particles repel each other with a force of 80 N, what are the charges on each of the two particles?
q1=8.05µC
q2=176 µC
*I know they don't add up to 185 but it took both of the answers as correct*
(b) If the two particles attract each other with a force of 80 N, what are the charges on the two particles?

I don't see why it wouldn't be the same answer except one of them would be negative.
According to F=k*$$\frac{|q_{1}*q_{2}|}{r^{2}}$$The type of charge doesn't matter when calculating force.

The product of the signs determine direction, as you observed.

So if the two particles are attracting each other with a force of 80 N, the charges must be equal in magnitude but opposite in sign. Therefore, the charges would be -8.05 µC and 176 µC. This ensures that the overall charge of the system is still 185 µC, but the forces are now attractive instead of repulsive.

## 1. What is an electric field?

An electric field is a physical quantity that describes the influence that a charged object has on other charged objects in its vicinity. It is defined as the force per unit charge experienced by a small test charge placed in the field.

## 2. How is an electric field created?

An electric field is created by a charged object, such as a particle with a positive or negative charge. The strength and direction of the electric field is determined by the amount and distribution of the charge.

## 3. What is the relationship between electric field and distance?

The strength of an electric field is inversely proportional to the square of the distance from the charged object. This means that as the distance from the charged object increases, the strength of the electric field decreases.

## 4. How does the presence of two point particles affect the electric field?

The presence of two point particles with opposite charges will create an electric field between them. The direction of the electric field will be from the positive particle to the negative particle. The strength of the electric field is determined by the charges of the particles and the distance between them.

## 5. What is the formula for calculating the electric field between two point particles?

The formula for calculating the electric field between two point particles is E = (kQq)/r^2, where E is the electric field strength, k is the Coulomb's constant, Q and q are the charges of the particles, and r is the distance between them. This formula assumes that the particles are point charges and that the medium surrounding them is vacuum.

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