Electric field at perpendicular distance R due to a Solenoid

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SUMMARY

The discussion centers on calculating the electric field at a perpendicular distance \( r \) from a solenoid carrying a time-varying current described by \( I = I_0 \sin(\omega t) \). Using Faraday's law, the relationship between the electric field \( E \) and the magnetic flux is established through the equation \( \int E \cdot dS = -\frac{1}{c} \frac{d}{dt}(\text{Magnetic flux}) \). The participant successfully derived the expression for \( E \) by substituting the magnetic flux with \( \mu_0 I_0 \sin(\omega t) \) and solving for \( E \) in the context of a circular path integral.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Knowledge of magnetic flux and its relation to electric fields
  • Familiarity with solenoids and their properties
  • Basic calculus for solving differential equations
NEXT STEPS
  • Study the derivation of electric fields from time-varying magnetic fields using Maxwell's equations
  • Explore the application of Lenz's Law in electromagnetic induction scenarios
  • Learn about the properties and applications of solenoids in electromagnetic devices
  • Investigate the role of the speed of light \( c \) in electromagnetic theory
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Students and educators in physics, particularly those focusing on electromagnetism, electrical engineers, and anyone interested in the practical applications of solenoids and electromagnetic induction.

ElijahRockers
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Homework Statement


A solenoid as viewed from the left has a current carrying wire wrapping around it counter clockwise. The current travels from left to right. The current varies as:

[tex]I[/tex]=[tex]I_0sin(wt)[/tex]

According to Faraday's law, this will result in electric field. From symmetry, the electric field on a concentric circle is constant, and the electric field lines are concentric. Apply Faraday's law on a concentric circle of radius r to find an expression for the electric field at a perpendicular distance r from the solenoid.


Homework Equations


I believe I am supposed to be using Faraday's Law:

Integral of E.dS = -d/dt(Magnetic flux)
(Sorry, still trying to figure out how to use latex.)

The Attempt at a Solution



Well, we just finished doing Lenz's Rule, and I was good up until he brought electric field into it. Do I have to replace E in terms of I? I guess I just really don't get it, and I can't find it anywhere in his online notes or on the web. Help!
 
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EDIT: I figured it out. I needed to use the equation Integral of E.dS = -1/c d/dt(Magnetic flux)where c is the speed of light. The integral was over a circular path, so it ended up being 2πrE = -1/c d/dt(Magnetic flux). From there, I replaced the magnetic flux with μ0I_{0}sin(wt) and solved for E.
 

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