Electric field at (x,y) from uniformly charged rod.

Click For Summary
SUMMARY

The discussion focuses on calculating the electric field at an arbitrary point (x, y) from a uniformly charged rod with charge Q distributed over its length L, positioned along the x-axis between x = ±L/2. The key equation used is ∫dE = ∫kdq/r², where the challenge arises from the ambiguity in defining variables such as k, λ, and a. Participants express confusion over the integration process and the program's ability to interpret user-defined variables, particularly in relation to the coordinate system.

PREREQUISITES
  • Understanding of electric fields and charge distributions
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of coordinate systems in physics
  • Experience with physics simulation software, such as Mastering Physics
NEXT STEPS
  • Study the derivation of electric fields from continuous charge distributions
  • Learn advanced integration techniques for solving physics problems
  • Explore the use of coordinate transformations in electric field calculations
  • Investigate the functionality and limitations of physics simulation tools like Mastering Physics
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone involved in computational physics, particularly those working with electric fields and charge distributions.

MusWolf
Messages
1
Reaction score
0

Homework Statement


A thin rod carries a charge Q distributed uniformly over its length L , and is situated on the x-axis between x=±L/2. Find the electric field at an arbitrary point (x, y). (You will have to do separate integrals for the x and y components.)

Homework Equations


∫dE=∫kdq/r2

The Attempt at a Solution


cm5lb9q.png

mk3g2IV.png

[/B]
Mastering Physics is telling me that the answer does not depend on k, lambda or a, which are variables I defined.

I have another method of attempting the question which results in a nasty integration, it's basically Mastering Physics being very ambiguous in what I am allowed to define. As seen here:

vTWYyvn.png
 
Physics news on Phys.org
Hello MW, :welcome:

A few questions to begin with: how would the program be able to understand how you defined ##a## and ##\lambda## ? Shouldn't you use ##y## and ##Q/L## instead ?

And I don't understand how you can redefine x in an x, y coordinate system ?

MusWolf said:
is telling me that the answer does not depend on k, lambda or a,
How does it do that ? Or is that a different program ?

Is your handwriting meant to be read by others than yourself ? I find it difficult ...
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
4K
Replies
6
Views
4K
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K