Electric field due to a finite line of charge

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SUMMARY

The discussion focuses on calculating the electric field due to a finite line of charge, specifically a line of length 2a centered on the x-axis with charge Q. The electric field at a point x on the x-axis is derived using the equation E = kQ/(x(x² + a²)^(1/2)). The user seeks clarification on integrating the expression dy/(x² + y²)^(1/2), which is resolved through the substitution y = x tan(θ), leading to the correct integration result of y/(x²(x² + y²)^(1/2)).

PREREQUISITES
  • Understanding of electric fields and Coulomb's law
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of trigonometric substitutions in integrals
  • Basic concepts of line charge distributions
NEXT STEPS
  • Study the derivation of electric fields from continuous charge distributions
  • Learn advanced integration techniques, focusing on trigonometric substitutions
  • Explore the application of electric field concepts in electrostatics
  • Investigate the effects of varying charge distributions on electric fields
USEFUL FOR

Students in physics, particularly those studying electromagnetism, as well as educators and anyone interested in the mathematical foundations of electric fields from charge distributions.

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Homework Statement


A line of length 2a on the y-axis centred in the middle of the x-axis with its ends at a and -a on the y axis, has been charged with charge Q. Work out the electric field at point x on the x axis.


Homework Equations


E=kdQ/r^2
dQ=Qdy/2a


The Attempt at a Solution


I have the answer in front of me: Qk*1/(x(x^2+a^2)^1/2)

I start with dE_x= kQxdy/2a(x^2+y^2)^3/2 (added the x component with x/(x^2+y^2)^1/2)
This integral is the bit I don't understand!

How do you integrate dy/(x^2+y^2)^1/2 ?
Apparently the answer is y/(x^2(x^2+y^2)^1/2). How does this work?

And it does give the correct answer if you follow it on. But How do you integrate that?


 
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To do this integral, use the substitution y = x tanθ and see what you get.
 

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