Electric Field Due To A Ring and Disk

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Homework Help Overview

The problem involves comparing the electric fields produced by a uniformly charged ring and a uniformly charged disk at a point along the axis of both shapes. The original poster is exploring how the electric field from the disk relates to that from the ring, considering the geometry and distribution of charge.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the contributions of infinitesimal rings that make up the disk and how their angles affect the resultant electric field. There is also speculation about the relationship between the distances involved (x and R) and the electric field strengths.

Discussion Status

Some participants are exploring the reasoning behind the electric field contributions from both the ring and the disk. There is an exchange of ideas regarding the implications of the geometry on the electric field strength, with no clear consensus reached yet.

Contextual Notes

Participants are considering the implications of the charge distribution and the distances involved, which may affect the comparison of the electric fields. There is uncertainty about how these factors influence the outcome.

Bashyboy
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Homework Statement


Assume a uniformly charged ring of radius R and charge Q produces an electric field Ering at a point P on its axis, at a distance x away from the center of the ring. Now the same charge Q is spread uniformly over a circular area the ring encloses, forming a flat disk of charge with the same radius. How does the Edisk produced by the disk at P compar with the field produced by the ring at the same point?

(a) Edisk < Ering

(b) Edisk = Ering

(c) Edisk > Ering

(d) Impossible to determine

Homework Equations





The Attempt at a Solution



My first suspicion was, that Edisk > Ering was the correct answer. This was so, because the disk can be thought of as many rings of infinitesmal size concentric. One infinitesmal ring would contribute to the electric field that is directed co-axially. This co-axial would begin to compound as you considered the remaining infinitesmal rings that constitute the entire disk.

Here is where came to a hault:

As you consider infinitesmal rings further from the center of disk, the angle that the infinitesmal ring makes with the x-axis becomes greater, thereby causing the co-axial component fo the electric field to dimish, as you move from the center of the disk.

In addition, I have this conjecture that the answer would also somehow depend on the relative of magnitude of x and R.

Could someone help me?
 

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Consider the vectors of the electric field that each small portion of the disk generates, and compare it to the vectors that each small portion of the ring generates.
 
Bashyboy said:
As you consider infinitesmal rings further from the center of disk, the angle that the infinitesmal ring makes with the x-axis becomes greater, thereby causing the co-axial component fo the electric field to dimish, as you move from the center of the disk.
I'm puzzled as to why you're puzzled. The charge on the ring is on average further from the centre than for the disk, giving the answer you have.
 
Bashyboy said:
My first suspicion was, that Edisk > Ering was the correct answer. This was so, because the disk can be thought of as many rings of infinitesmal size concentric. One infinitesmal ring would contribute to the electric field that is directed co-axially. This co-axial would begin to compound as you considered the remaining infinitesmal rings that constitute the entire disk.


Well, I wasn't sure if this idea conflicted with is one:



Bashyboy said:
As you consider infinitesmal rings further from the center of disk, the angle that the infinitesmal ring makes with the x-axis becomes greater, thereby causing the co-axial component fo the electric field to dimish, as you move from the center of the disk.

In addition, I have this conjecture that the answer would also somehow depend on the relative of magnitude of x and R.
 
Bashyboy said:
Well, I wasn't sure if this idea conflicted with is one:

Seems to me they agree.
 
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