Electric field (easy at least I thought so)

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SUMMARY

The electric field strength at a distance of 10.0 cm from a long charged wire is calculated using Gauss's law. The initial electric field strength of 2000 N/C at 5.0 cm does not decrease by a factor of 1/4 when the distance doubles, as the user initially assumed. Instead, the correct approach involves recognizing that the electric field due to an infinitely long charged wire is independent of the radius, leading to a consistent electric field strength. The formula to use is derived from Gauss's law, which states that the electric field E is proportional to the linear charge density and inversely proportional to the distance from the wire.

PREREQUISITES
  • Understanding of electric fields and their properties
  • Familiarity with Gauss's law
  • Knowledge of vector components in physics
  • Basic calculus for deriving formulas
NEXT STEPS
  • Study Gauss's law and its applications in electrostatics
  • Learn how to derive electric field equations for different charge distributions
  • Explore the concept of electric field lines and their significance
  • Investigate the differences between point charges and line charges in electric field calculations
USEFUL FOR

Students of physics, educators teaching electromagnetism, and anyone interested in understanding electric fields and their calculations.

Kalie
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The electric field strength 5.0 cm from a very long charged wire is 2000 N/C.
What is the electric field strength 10.0 cm from the wire?

Okay I thought that since the radius is double what it was before using the equation:

E= K*q*(r head)/(r^2)

I said that it decreases 1/4 and becomes 500.

Thats wrong. But obviously because I ignored r head...the vector thingy. But how do I apply it to the equation and solve for its new value?

Sigh...confused
 
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think about the symmetry... for a point charge the field is distributed in all direction (a spherical gaussian surface), for a line of charges (the lateral surface of a cylinder)... so in other words, you have used the wrong formula. Use Gauss's law to derive a new a formula (E as a fn of r)
 

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