Electric field in a spherical shell

[curiosissimo]

Homework Statement

We have a spherical shell with 2 radiuses $$R_1<R_2$$ The charge Q is distributed uniformly in the part of the sphere between R1 and R2. The inner space of the sphere ($$0<y<R_1$$) has no charge What is the electric field in the spherical shell?

Relevant Equations

Gaussian theorem

So for the Gaussian theorem we know that $$ \frac{Q}{e} = \vec E \cdot \vec S $$ Q's value is known so we don't need to express it as $$Q=(4/3)\pi*(R_2 ^3-R_1 ^3)*d$$ where d is the density of the charge in the volume. I've expressed the surface $$S=4\pi*x^2$$ where x is the distance of a point in the shell from the center of the sphere. So we simply get $$E=\frac{Q}{e*4\pi*x^2}$$ but it's wrong and I really don't know why. Thanks in advance!

 

[TSny]

Hello, curiosissimo. Welcome to PF.

Don't confuse the total charge of the shell with the charge enclosed by the Gaussian surface.

 

[curiosissimo]

Hello, curiosissimo. Welcome to PF.

Don't confuse the total charge of the shell with the charge enclosed by the Gaussian surface.

Of course! What a silly mistake! Thank you very much!