Danen
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So I just wanted to clarify:
Because D = ε0E + P
P being zero in vacuum
and ∇D is constant regardless of medium
if D was originally in a vacuum, the corresponding E would be greater than if it were in an insulating medium. So,
E in vacuum > E in medium
Because D = ε0E + P
P being zero in vacuum
and ∇D is constant regardless of medium
if D was originally in a vacuum, the corresponding E would be greater than if it were in an insulating medium. So,
E in vacuum > E in medium