Electric field in special relativity

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SUMMARY

The discussion focuses on the derivation of the electric field E' produced by a charge q at rest in one inertial frame and moving in another frame O' with velocity βc. The electric field is expressed as E' = γ*q*(x',y',z')/(4πεo*γ²(x'²+y'²+z'²)^(3/2)). The user seeks to manipulate this equation to show that E' can also be represented as E' = q*r'/(4πεo*γ²*r'²(1-βsin²θ)*r'). The challenge lies in the transformation of coordinates and the application of the Lorentz factor γ.

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Hello,

Homework Statement



A charge q is at rest in frame O. In O' with velocity βc in x direction, at t'=0 the charge is at the origine O' and produce an electric field E' at position r'=(x',y',z') :
E'=γ*q*(x',y',z')/(4πεo*γ²(x'²+y'²+z'²)3/2)
If θ is the angle between r' and x, show that:
E'=q*r'/(4πεo*γ²*r'²(1-βsin²θ)*r')


Homework Equations





The Attempt at a Solution


I'm blocking at this step :
E'=q*r'/(4πεo*γ²*(x'²+(y'²+z'²)/γ²)^3/2)
sinθ=y'/r' but I can't find a way to find the asked formula, I think that there's something that I'm missing but don't know what.
Thanks
 
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