Electric field magnitude for electron accelerating 4.50 m in 3.00 μs

[hitek131]

I need help with this question if anyone can give me an idea of what to do. Any help would be greatly appreciated.

An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.50 m in the first 3.00 micro seconds after it is released.
What is the magnitude of the electric field?

 

[inha]

Do you know what force is in charge of accelerating the electron?

 

[hitek131]

yes it is F=E * q

I know that q = 1.62 * 10^-19, but I still have an unknown variable.

 

[inha]

You can solve the acceleration using elementary kinematics. Then you'd need to relate that force to the acceleration you solved for.

 

[hitek131]

yes i know, you use y = 1/2at^2, but you still get unknown variables

 

[inha]

You know everything besides E. The electron's mass is standard tabulated stuff.

 

[hitek131]

Is the mass 9.10938188(72) * 10 ^-31?

 

[inha]

yeah that's it. it's all algebra from here on.

 

[hitek131]

Thank you so much!