Electric Field of a Conducting Slab

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SUMMARY

The discussion centers on calculating the electric field, E(r), above a horizontal conducting slab with a charge Q positioned at height b above it. The participants confirm that the electric field above a plane can be expressed as σ*r/(2*ε₀), where σ is the surface charge density and ε₀ is the permittivity of free space. They emphasize the importance of boundary conditions, noting that the electric field must be continuous at the surface of the slab and zero at infinity. The method of image charges is suggested as a potential solution approach for this problem.

PREREQUISITES
  • Understanding of electric fields and Gauss' Law
  • Familiarity with boundary conditions in electrostatics
  • Knowledge of the method of image charges
  • Concept of surface charge density (σ) and permittivity of free space (ε₀)
NEXT STEPS
  • Study the application of Gauss' Law in electrostatics
  • Explore the method of image charges for solving electrostatic problems
  • Learn about boundary conditions in electrostatics and their implications
  • Investigate the properties of electric fields around conductors
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Students and professionals in physics, particularly those studying electrostatics, electrical engineers, and anyone involved in solving problems related to electric fields and conductors.

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Homework Statement



A charge Q is placed at height b abouve a plane horizontal conducting slab.

Write down the electric field, E(r), at a general point r above the slab (taking the point r=0 to be the point on the slab directly beneath the charge), and show that it satisfies the appropriate boundary conditions.

Homework Equations





The Attempt at a Solution



Ok, I know that the electric field above a plane is sigma*r/2*epsilon_zero*r, but since this slab has a thickness where there will be no electric field, does this make a difference? Can I still use Gauss' Theorem? And what does it mean by "appropriate boundary conditions"? Just that it's continuous at the surface of the slab and zero at infinity?

Just, generally, where do I start with this question?

Thanks
 
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For this type of problem one usually assumes that the thickness of the slap is negligible. In other words, one can consider the slab an equipotential plane.

Note that since this slab is a conductor an electric field will be induced on this plane. What can you say about this electric field?
 
Is this supposed to be solved by the method of image charges, or that is something completely different?

Well the charge induced at the surface of the slab will have the same magnitude as the point charge above it. But i am not sure what that tells me about the field since the geometry of the slab is different then the one of the point charge obviously

( I have problems with something very similar so thought to jump in if that's ok.. )
 

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