Electric field of a dipole, two different equations?

AI Thread Summary
The discussion centers on the two different equations for the electric field of a dipole. The first equation presented is E = k p [2cos θ r + sin θ θ]/(r^3), while the second is E = k[3(p·r) r - p]/(r^3). Participants explore how to convert the first equation into the second, suggesting that using the relationship between unit vectors and trigonometric terms may be key. A geometric relationship is highlighted, showing that z can be expressed in terms of r and θ, facilitating the conversion. Understanding these equations is crucial for accurately describing the electric field generated by dipoles.
gareth182
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Electric field of a dipole, two different equations??

Hi,

I've been taught in uni how to derive the electric field of a dipole to be

E= k p [2cos theta r(hat) + sin theta theta(hat)]/(r^3)

where k=1/(4pi e0), p=qd= dipole moment, (hat) terms are unit vectors and r is the distance between the halfway point of the dipole and the point of observation.

However, on most internet pages the electric field is expressed as

E= k[3(p.r(hat))r(hat) - p]/(r^3)

can anyone help me convert the first electric field equation to the second?

I'm guessing it may involve using r(hat)=r/r to convert the trigonometric terms back to dot products...
 
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Sorry, I've got to use underlines instead of hats to denote unit vectors. The two expressions you have are

(1) E = kp[2 cos θ r + sin θ θ]/r3 and
(2) E = kp[3 (z·r) r - z]/r3 = kp[3 cos θ r - z]/r3

Geometry tells us that z = cos θ r - sin θ θ, so plug that in (2) and you get (1).
 
It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
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