Electric field of Continuous charge Distribution

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SUMMARY

The discussion focuses on calculating the electric field generated by a semicircular continuous charge distribution with a linear charge density described by λ(θ) = λ0cosθ. The total charge on the semicircle is specified as 13.2 µC, leading to the determination of λ0, which is calculated to be 1.14e-05 C/m. The challenge arises in calculating the total force on a point charge of 3.11 µC placed at the center of curvature, specifically in setting up the integral for the force due to the charge distribution.

PREREQUISITES
  • Understanding of electric fields and forces in electrostatics
  • Familiarity with integral calculus for setting up and solving integrals
  • Knowledge of linear charge density and its implications in electric field calculations
  • Concept of charge distributions and their effects on point charges
NEXT STEPS
  • Study the derivation of electric fields from continuous charge distributions
  • Learn how to set up integrals for calculating forces in electrostatics
  • Explore the application of Coulomb's law in non-point charge scenarios
  • Investigate the use of symmetry in simplifying electric field calculations
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone involved in electrostatics, particularly those tackling problems related to continuous charge distributions and electric fields.

amninder15
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A line of positive charge is formed into a semicircle of radius R = 57.8 cm, as shown in the figure below. (The figure is a semicircle above the x-axis with angle θ measured from positive y
axis centred at the origin)

The charge per unit length along the semicircle is described by the expression λ(θ) = λ0cosθ. The total charge on the semicircle is 13.2 µC.
(a) Calculate the value of the constant λ0.
(b) Calculate the total force on a charge of 3.11 µC placed at the center of curvature.

I did part a i found the answer 1.14e-05 C/m. but for part (b) i can't seem to setup the integral

any help would be appreciated.
 
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You need to find the force due to a small part of the semi-circle at angle θ which is inside the arc Rdθ, then integrate that over the whole range of θ.

Where do you get stuck?
 

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