Electric Field on finite charged rod

Click For Summary

Homework Help Overview

The problem involves a thin charged rod with a length of 100 cm and a total charge of 37 nC, where the charge density is proportional to the square of the distance from one end of the rod. The objective is to determine the electric field at the end of the rod.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of the charge density and whether the value of k can be determined by substituting values. There is uncertainty about the implications of evaluating the electric field at the end of the rod, particularly whether it results in zero electric field due to the position being at the origin of the charge distribution.

Discussion Status

The discussion includes attempts to clarify the approach to finding the electric field, with some participants suggesting the need for integration over the length of the rod to account for the varying charge density. There is a recognition that the formulas used may not apply directly due to the specific conditions of the problem.

Contextual Notes

Participants note that the electric field formula used is valid for infinite uniformly charged wires, which does not apply to this scenario. There is also mention of the total charge constraint and the need to integrate the charge density to find k.

n0va
Messages
7
Reaction score
0

Homework Statement


Thin rod AB has length L=100 cm and total charge q0=37 nC that is distributed in such a way that its line density [itex]\lambda[/itex] is proportional to the square of the distance from the end A, i.e. [itex]\lambda[/itex](x) =kx^2. Determine electric field E at the end A of the rod.

Homework Equations



E = (1/(4pi[itex]\epsilon[/itex]0))
Electric Field for a thin uniformly charged conducting wire: E = [itex]\lambda[/itex]/(2[itex]\pi[/itex]r[itex]\epsilon[/itex]0)

The Attempt at a Solution



if [itex]\lambda[/itex](x) =kx^2 , can we find k by plugging in 1m in x and setting it equal to 37. meaning k is 37.

Since they are asking for the E at point A, is x just 0? and does that mean that E is 0?
 
Physics news on Phys.org
Does my answer make any sense at all? Or am i misinterpreting it? They're asking for the E field on point A, and since the distribution starts at A, x at that point is 0 and therefore there is no electricfield at point A?
 
Cmon seriously?
 
Hello n0va.

Welcome to Physics Forums (PF).

Did you read the https://www.physicsforums.com/showthread.php?t=94379", particularly #3 in this case.

To find k, you must integrate over the length of the charged rod & solve for k.[tex]Q=\int_{0m}^{1m}{kx^2}\,dx[/tex]

The formula you used to find E gives the E field at a distance, r, from an infinitely long charged rod which has uniform linear charge density.

To do this problem, you will have to do an integration over the length of the rod.
 
Last edited by a moderator:
I suggest you to reread your posts before you send them and check the validity of your statements.

n0va said:

Homework Equations



E = (1/(4pi[itex]\epsilon[/itex]0))

What is E? If it denotes the electric field strength how can it be the same for all situations?

n0va said:
Electric Field for a thin uniformly charged conducting wire: E = [itex]\lambda[/itex]/(2[itex]\pi[/itex]r[itex]\epsilon[/itex]0)

This formula is valid for an infinite uniformly charged wire, at a distance r from it. The wire in the problem is neither infinite nor uniformly charged and the field is asked at zero distance from it, at one end.

n0va said:

The Attempt at a Solution



if [itex]\lambda[/itex](x) =kx^2 , can we find k by plugging in 1m in x and setting it equal to 37. meaning k is 37.

No, it is not right. The total charge is given. The integral of the charge density along the wire length is equal to the total charge, 37 nC, as SammyS suggested.

n0va said:
Since they are asking for the E at point A, is x just 0? and does that mean that E is 0?

The electric field has some contribution for all parts of the wire.

ehild
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
4K
Replies
3
Views
2K
Replies
4
Views
4K
  • · Replies 16 ·
Replies
16
Views
2K
Replies
6
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K