Electric field, surface charge density

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SUMMARY

The discussion centers on understanding the relationship between electric potential difference (ΔV) and electric field (E) in the context of surface charge density. The key equation ΔV = -∫E dl is highlighted, with a specific focus on expressing E in terms of the electric displacement field (D). Participants emphasize the application of Gauss' law for D to derive an explicit expression for D based on the free charge Q on the inner conductor, clarifying the derivation process for the potential difference.

PREREQUISITES
  • Understanding of electric fields and potentials
  • Familiarity with Gauss' law
  • Knowledge of electric displacement field (D)
  • Basic calculus for evaluating integrals
NEXT STEPS
  • Study the derivation of electric displacement field (D) using Gauss' law
  • Learn about the relationship between electric field (E) and electric potential (V)
  • Explore applications of surface charge density in electrostatics
  • Investigate advanced topics in electrostatics, such as boundary conditions
USEFUL FOR

Students and professionals in physics, electrical engineering, and anyone studying electrostatics or electric fields and potentials.

Cocoleia
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Homework Statement


upload_2017-2-26_12-51-39.png


Homework Equations

The Attempt at a Solution


I have the full solution, the first part being:
upload_2017-2-26_12-52-38.png

I don't understand how they came up with the expression for Vab. I know usually ΔV=-∫E dl, but I'm not sure how they found their expression. Can someone explain? Thanks.
 
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Cocoleia said:
I know usually ΔV=-∫E dl, but I'm not sure how they found their expression.
Yes, you can think of their expression as coming from ΔV=-∫E dl if you express E in terms of D. Use Gauss' law for D to obtain an explicit expression for D in terms of the free charge Q on the inner conductor.
 

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