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Electric field, surface charge density

  1. Feb 26, 2017 #1
    1. The problem statement, all variables and given/known data

    2. Relevant equations

    3. The attempt at a solution
    I have the full solution, the first part being:
    I don't understand how they came up with the expression for Vab. I know usually ΔV=-∫E dl, but i'm not sure how they found their expression. Can someone explain? Thanks.
  2. jcsd
  3. Feb 26, 2017 #2


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    Yes, you can think of their expression as coming from ΔV=-∫E dl if you express E in terms of D. Use Gauss' law for D to obtain an explicit expression for D in terms of the free charge Q on the inner conductor.
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