Electric field, surface charge density

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Cocoleia
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Homework Statement


upload_2017-2-26_12-51-39.png


Homework Equations

The Attempt at a Solution


I have the full solution, the first part being:
upload_2017-2-26_12-52-38.png

I don't understand how they came up with the expression for Vab. I know usually ΔV=-∫E dl, but I'm not sure how they found their expression. Can someone explain? Thanks.
 
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Cocoleia said:
I know usually ΔV=-∫E dl, but I'm not sure how they found their expression.
Yes, you can think of their expression as coming from ΔV=-∫E dl if you express E in terms of D. Use Gauss' law for D to obtain an explicit expression for D in terms of the free charge Q on the inner conductor.