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drprevet
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Homework Statement
A proton's speed as it passes point A is 4.90×104 . It follows the trajectory: Point A @ 30V through Point B @-10V. What is the proton's speed at point B?
Homework Equations
deltaV=deltaK/q
V=40
vi=4.9*10^4
q=1.6*10^-19
m=1.67*10^-27
deltaK=1/2mvf^2-1/2mvi^2
The Attempt at a Solution
40=(0.5)(1.67*10^-27)(vf^2)-=(0.5)(1.67*10^-27)(4.9*10^4)/1.6*10^-19
velocity final=8.75*10^4