# Electric Field Velocities from Point A to Point B

## Homework Statement

A proton's speed as it passes point A is 4.90×104 . It follows the trajectory: Point A @ 30V through Point B @-10V. What is the proton's speed at point B?

## Homework Equations

deltaV=deltaK/q
V=40
vi=4.9*10^4
q=1.6*10^-19
m=1.67*10^-27
deltaK=1/2mvf^2-1/2mvi^2

## The Attempt at a Solution

40=(0.5)(1.67*10^-27)(vf^2)-=(0.5)(1.67*10^-27)(4.9*10^4)/1.6*10^-19

velocity final=8.75*10^4

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ehild
Homework Helper
The calculation is easier if you factor the right side of the equation:

$$40=\frac{0.5*1.67\cdot 10^{-27}}{1.6\cdot 10^{-19}}(v^2-(4.9\cdot 10^4)^2)$$

and then simplify.

ehild