Electric field with dielectric constant

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SUMMARY

The discussion focuses on calculating the electric field and charge for a capacitor with a dielectric material, specifically Mylar, between its plates. The capacitor consists of two 5.0mm x 5.0mm electrodes separated by a 0.10mm thick Mylar sheet, with a dielectric constant (k) of 3.1, connected to a 9.0 V battery. The charge before the Mylar is withdrawn is 62 pC, while the charge after withdrawal is 20 pC. The electric field is uniform between the plates, and its relationship with voltage and distance is critical for accurate calculations.

PREREQUISITES
  • Understanding of capacitor equations, specifically C={k(epsilon_o)A}/d
  • Knowledge of charge calculation using Q=CV
  • Familiarity with dielectric materials and their impact on capacitance
  • Basic principles of electric fields and their relationship to voltage and distance
NEXT STEPS
  • Study the impact of different dielectric materials on capacitance and electric fields
  • Learn about the relationship between voltage, electric field, and plate separation in capacitors
  • Explore advanced capacitor configurations and their applications in circuits
  • Investigate the effects of varying dielectric constants on charge storage capabilities
USEFUL FOR

This discussion is beneficial for physics students, electrical engineering students, and anyone interested in understanding capacitor behavior with dielectric materials in practical applications.

quietriot1006
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Homework Statement


Two 5.0mm*5.0mm electrodes with a 0.10mm thick sheet of Mylar between them are attached to a 9.0 V battery. Without disconnecting the battery, the Mylar is withdrawn. (Very small spacers keep the electrode separation unchanged.) Dielectric constant for Mylar is k=3.1. What is the charge before and after the Mylar is withdrawn?
What is the electric field before and after the mylar is withdrawn?

Homework Equations


C={k(epsilon_o)A}/d
Q=CV
C=kC_o


The Attempt at a Solution


I get the charges correctly but i just can't get the electric field before and after. Charge before is 62 pC and after its 20 pC. Help please.
 
Physics news on Phys.org
The electric field E is uniform between the two "plates". There is a simple relation between V, E, and the distance d between the plates.
 

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