Electric Field Work on Moving Charge

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SUMMARY

The electric field does 40 J of work on a charge moving from point A to point B over a distance, d. When the charge moves from point C to point D over a distance of 2d, the work done cannot simply be assumed to be doubled to 80 J. The actual work depends on the angle between the force and the path taken, as described by the equation W = ∫ F·ds = ∫ |F| |ds| cos(θ). Without knowing the direction of the paths relative to the electric field, the work done cannot be accurately calculated.

PREREQUISITES
  • Understanding of electric fields and forces
  • Familiarity with the work-energy principle
  • Knowledge of vector calculus, particularly line integrals
  • Basic physics concepts related to charge movement in electric fields
NEXT STEPS
  • Study the work-energy theorem in the context of electric fields
  • Learn about vector calculus and line integrals
  • Explore the concept of electric field direction and its impact on work done
  • Investigate examples of work done on charges in varying electric field configurations
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Students studying physics, particularly those focusing on electromagnetism, as well as educators looking to clarify concepts related to work done by electric fields on moving charges.

david84
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Homework Statement



An electric field does 40 J of work on a charge moving from point A to point B in a straight line at a distance, d. If the charge moves through a different path from point C to point D at a distance of 2d, what is the work done on the charge?

Homework Equations



W=Fd

The Attempt at a Solution



I figure that because the distance is doubled, the work done will be doubled as well according to the work equation. So the total work done will be 40 J x 2 = 80 J. I'm not completely sure though cause I feel like I'm missing something. Is the question really this simple, and do I have the right answer? Thanks.
 
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david84 said:

Homework Statement



An electric field does 40 J of work on a charge moving from point A to point B in a straight line at a distance, d. If the charge moves through a different path from point C to point D at a distance of 2d, what is the work done on the charge?

Homework Equations



W=Fd

The Attempt at a Solution



I figure that because the distance is doubled, the work done will be doubled as well according to the work equation. So the total work done will be 40 J x 2 = 80 J. I'm not completely sure though cause I feel like I'm missing something. Is the question really this simple, and do I have the right answer? Thanks.
Welcome to PF David!

You do not have enough information to answer the question. We need to know the direction of the paths relative to the field E at all points in the path. This is because:

[tex]Work = W = \int \vec{F}\cdot d\vec{s} = \int |\vec{F}| |d\vec{s}|\cos\theta[/tex]

over a given path, where [itex]\theta[/itex] is the angle between the Force and the path.

AM
 

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