Electric Flux of Two Hemispheres with different radii

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SUMMARY

The discussion centers on the electric flux through an annular ring (surface 3) formed by two hemispherical surfaces with different radii, r1 and r2, centered around a point charge. The electric field due to the point charge is described by the equation E⃗ (r⃗ )=C/r^2 r_hat, where C is a constant proportional to the charge. Participants clarify that the electric field lines are parallel to surface 3, resulting in an angle of 90 degrees between the area vector and the electric field vector, leading to zero electric flux through surface 3. The confusion arises from the interpretation of the angle between the area vector and the electric field vector.

PREREQUISITES
  • Understanding of electric flux and Gauss's Law
  • Familiarity with electric field equations, specifically E⃗ (r⃗ )=C/r^2 r_hat
  • Knowledge of vector analysis, particularly area and electric field vectors
  • Concept of point charges and their electric fields
NEXT STEPS
  • Study the application of Gauss's Law in different geometries
  • Learn about electric field lines and their properties
  • Explore vector calculus, focusing on dot products and angles between vectors
  • Investigate the implications of electric flux in various physical scenarios
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone seeking to deepen their understanding of electric fields and flux in relation to point charges.

Inveritatem
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Homework Statement


Two hemispherical surfaces, 1 and 2, of respective radii r1 and r2, are centered at a point charge and are facing each other so that their edges define an annular ring (surface 3), as shown.

1006820_01.jpg

Homework Equations


The field at position r⃗ due to the point charge is:

E⃗ (r⃗ )=C/r^2 r_hat

where C is a constant proportional to the charge, r=∣∣r⃗ ∣∣, and r_hat=r⃗ /r is the unit vector in the radial direction.

The Attempt at a Solution


The hints imply that because the electric field lines everywhere are parallel to the annular ring (surface 3), the angle between the area and electric field vector is 90, which implies that the flux through surface 3 is 0. I am confused as to why this is the case, as looking at the picture I only see one possibility:

From the side view, the electric field lines seem to only go through surface 1, meaning no electric field passes the surface of surface 3, which leads to 0 electrical flux.

Can anyone help explain why there are electrical field lines that form a 90 degree angle with the area vector?
 
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Inveritatem said:
Can anyone help explain why there are electrical field lines that form a 90 degree angle with the area vector?
Be sure you understand the convention for the direction of an area vector.

In the side view picture, pick any point on surface 3 and draw the area vector for a small patch of area at that point. Also draw the direction of the field at that point.

EDIT: I think the confusion is with the wording of the hint. It should have said the the angle between the area vector and the electric field vector is 90o.
 
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