- #1

jimen113

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## Homework Statement

A uniformly charged insulating rod of length 14cm is bent into the shape of a semicircle (looks like a "C"). The rod has a total charge of (-7.50E-6C). find the electric potential at O, the center of the semicircle

## Homework Equations

v= ke[tex]\int[/tex]dq/r

## The Attempt at a Solution

after integrating I get: KeQ/r

=Ke(-7.50E-6)/(0.14m)

For the semicircle will the radius be 0.7m? I'm frustrated with this problem and maybe I'm just making a dumb calculation mistake.

The answer is: -1.51MV

Thank you in advance! :shy: