Electric Potential and Consv of Energy, Is this right?

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Homework Help Overview

The discussion revolves around a problem involving the electric potential and conservation of energy, specifically concerning a proton being brought to rest by an electric field. Participants are exploring the implications of energy conservation in the context of external forces acting on the system.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of kinetic energy and the potential difference required to stop the proton. There are questions about the conservation of energy when external forces are present, and the definition of the system in relation to the electric field.

Discussion Status

The discussion is active, with participants providing feedback on calculations and questioning the assumptions regarding energy conservation. Some guidance has been offered regarding the nature of electric fields and their classification as conservative forces, but no consensus has been reached on the implications of external forces.

Contextual Notes

Participants are considering the role of external forces in the conservation of energy and whether the electric field's source should be included in the system. There is an ongoing debate about the definitions and boundaries of the system in this context.

ryan8642
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Homework Statement


A proton with an intial speed of 800,000m/s is brought to rest by an electric field.
What was the potential difference that stopped the proton.

Homework Equations


Ki + qvi = Kf + qvf

k=.5mv^2

The Attempt at a Solution



Voltage final = ?
vi = 800,000m/s
v2=0
q=1.60x10^-19
m=1.67x10^-27

ki=.5mv^2
=.5(1.67x10^-27)(800,000)
=6.68x10^-22j

Ki + qVi = Kf + qVf
Ki=-qVi
6.68x10^-22j=(-1.60x10^-19)Vi
-4.175x10^-3=Vi

^^^ is that answer correct?
Its seems weird cause Energy isn't really conserved :s

Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited:
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You forgot to square the velocity when you were working out the Kinetic Energy.
 
thank you very much, :)
answer makes more sense now V=-3340V
 
but why will the energy is conserved?
Isn't external force acting on proton?

whats your system?
 
cupid.callin said:
but why will the energy is conserved?
Isn't external force acting on proton?

whats your system?

The "system" is the proton in the electric field. Electric fields are conservative.
 
they are conservative ,,, but energy is only conserved only when internal conservative forces act on the system,

here (acc. to your system) external forces are also acting.
So: Δ(mechanical energy) = work done by external forces
 
cupid.callin said:
they are conservative ,,, but energy is only conserved only when internal conservative forces act on the system,

here (acc. to your system) external forces are also acting.
So: Δ(mechanical energy) = work done by external forces

What external forces would those be?
 
gneill said:
The "system" is the proton in the electric field. Electric fields are conservative.

in the electric field ...
So you mean that whatever is causing electric field is not a part of system, right?

then wouldn't electric force be an external force? ...? :confused:
 
cupid.callin said:
in the electric field ...
So you mean that whatever is causing electric field is not a part of system, right?

then wouldn't electric force be an external force? ...? :confused:

Is the Earth part of the system that contains its gravitational field? Must we abandon conservation of energy when a projectile mass arcs through the Earth's field?
 
  • #10
but in that case we include Earth in our system, don't we?
 
  • #11
cupid.callin said:
but in that case we include Earth in our system, don't we?

More like we ignore it for practical reasons since we consider its mass to be so great that it is unperturbed. It is included when necessary (celestial mechanics, for example), but taken as a whole, when everything is included, the gravitational field is still conservative with regards to potential.

Regarding this question, the electric field is presented as a constant background, just as we take the Earth's gravitational field to be a constant background for our 'lab' experiments.
 

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