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fal01
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Homework Statement
A proton is released from rest in a uniform
electric field of magnitude 40000V/m di-
rected along the positive x axis. The proton
undergoes a displacement of 0.3 m in the di-
rection of the electric field
The mass of a proton is 1.672623×10−27 kg
A.Find the change in the electric potential
if the proton moves from the point A to B.
Answer in units of V.
B.Find the change in potential energy of the
proton for this displacement. Answer in units
of J.
C.Apply the principle of energy conservation to
find the speed of the proton after it has moved
0.5 m, starting from rest. Answer in units of
m/s.
Homework Equations
V=Ed
U=qV
Kf-Ki+u=0
k=.5mv^2
Q
The Attempt at a Solution
A.) E=40000 V/m
d=.3m
mp=1.672623*10^-27kg
q=1.60218*10^-19
V=Ed
V=(40000)(.3)=12000V ---but that is wrong
B.)
U=qV
C.)
Kf-Ki+U=0
.5mv^2+U=0