Electric Potential (Conceptual question)

Click For Summary
SUMMARY

The discussion focuses on deriving the equation for electric field strength (E) using the formula E = Δv/d, where Δv represents the change in electric potential and d is the distance. The relationship ΔEp = -ΔEk indicates that the change in electric potential energy is equal to the negative change in kinetic energy. The negative sign in the derivation is crucial as it signifies the direction of energy transfer, emphasizing that electric potential decreases as kinetic energy increases. Understanding this relationship is essential for solving electrostatics problems effectively.

PREREQUISITES
  • Understanding of electrostatics concepts
  • Familiarity with the relationship between electric potential energy and kinetic energy
  • Knowledge of the formula E = Δv/d
  • Basic calculus for deriving equations
NEXT STEPS
  • Study the derivation of electric potential energy equations
  • Learn about the implications of negative signs in physics equations
  • Explore the concept of electric fields and their relation to potential
  • Investigate the principles of conservation of energy in electrostatics
USEFUL FOR

Students studying physics, particularly those focusing on electrostatics, as well as educators seeking to clarify concepts related to electric potential and energy transformations.

Fizickstudent
Messages
2
Reaction score
0

Homework Statement


To find "E" in an electrostatics problem when you are given the velocities and/or distance, you would use the formula E = Δv/d.

Given the information below to start out with, derive the equation E = Δv/d and explain what happens to the negative signs (where do they go and why) as you continue to derive the equation.

Given information:
ΔEp = -ΔEk
Δv/d = Eki - Ekf
Δv/d = -1/2mvf^2



Homework Equations


E = Δv/d

The Attempt at a Solution


For me to derive this equation any further to the equation E = Δv/d I will have to somehow get rid of that negative, I was just wondering, what happens to that negative?
 
Physics news on Phys.org
In the given problem delta v is not the change in velocity, but change in potential . Please go through the definition of electric potential at any point due to a charge.
 

Similar threads

Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
3K