Electric Potential Energy Concept

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SUMMARY

The discussion confirms that electric potential is a scalar quantity, as it lacks direction. It is established that one can assign a value of zero to electric potential at the origin, depending on the chosen reference point. The change in a particle's potential energy is indeed path-independent, as expressed by the equation U = qV, where V is contingent on the distance between two points. The work required to move a charge q from potential Vi to Vf is accurately represented as q(Vf - Vi), with the understanding that this reflects the work done against the electric force.

PREREQUISITES
  • Understanding of electric potential and potential energy concepts
  • Familiarity with scalar and vector quantities in physics
  • Knowledge of the relationship between work, charge, and electric potential
  • Basic grasp of reference points in electric fields
NEXT STEPS
  • Study the concept of electric potential energy in electrostatics
  • Learn about the implications of reference points in electric potential
  • Explore the mathematical derivation of U = qV
  • Investigate the differences between work done by electric fields and opposing forces
USEFUL FOR

Students of physics, educators teaching electromagnetism, and professionals in electrical engineering will benefit from this discussion on electric potential energy concepts.

r0306
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I'm unsure if the following is true or not in the absence of external forces:
  • Electric potential is a scalar quantity.
This I know is true because there is no direction associated with potential energy.
  • It is always possible to assign a value of zero to the electric potential at the origin.
This I am completely unsure of though I think it is true because potential depends on a reference point that you can set yourself.
  • The change in a particle's potential energy depends on the total length of its path between two points.
I suspect that this is true because U = qV and V is dependent on the distance between the points.
  • The work required to move a charge q from a point at potential Vi to a point at potential Vf is q(Vf - Vi).
This should be false because (delta)U = q(Vf - Vi) and W = -(delta)U so it should be -q(Vf - Vi) instead.

Can someone please verify my reasoning and correct me if I'm wrong? Thank you.
 
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q(Vf - Vi) is correct for the work done by the force opposing the electric force. If the work done by electric field was being considered, it would be q(Vi - Vf).
 
TESL@ said:
q(Vf - Vi) is correct for the work done by the force opposing the electric force. If the work done by electric field was being considered, it would be q(Vi - Vf).
That means all of the points listed are true then? I'm really uncertain about the second point.
 
Your second point is true as long as you offset the potentials of all the charges in the system wrt. the ground you take.
 
what did u end up getting for this?
 

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