Electric Potential: Find V between 6.17 nC & -4.32 nC Charges

[shaka23h]

Homework Statement

Two pont charges of magnitude 6.17 nC and -4.32 nC are separated by 29.1 cm. The acceleration of gravity is 9.8 m/s^2. the Coulomb constant is 8.98755 x 10 ^9 N m^2/C^2. What is the electric potential at a point midway between the charges? Answer in units of V.

Homework Equations

well I know Columb's law obviously comes into effet. If its just finding the electric force of repulsion between the 2 object it would be ez. But the potential? IS the acceleration of gravity even relevant in this problem?

The Attempt at a Solution

I know that (electric potential ) V = kq/ r and Columb's equation is F = Kq1q2/r^2. How can I manipulate both of these equations?

Thanks

 

[turdferguson]

I don't know why they threw in gravity, just add up the voltages. Coulombs law does not need to be manipulated

 

[shaka23h]

So do I just use V = Kq/r and solve for 6.17 and -4.32 making sure that I keep the signs? and then add these up? The question asked for the midway between charges how does this come into effect? is my r value 1/2 of 29.1 cm?

Let me know

 

[turdferguson]

Yes, but positive/negative orientation of distance doeesnt matter. The distance is positive for both voltages. Needless to say, youll wind up with a positive answer