Electric Potential in circuit

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SUMMARY

The discussion centers on the concept of electric potential in circuits, specifically addressing the equation for electric potential, V(p) = k ∑ (q_i / r_i), and its application in simple circuit models. It highlights a contradiction where points a and b in a circuit are considered neutral with no net charge, yet there is a voltage difference (ε) between them. The conclusion drawn is that the electric potential formula applies to point charges rather than continuous charge distributions found in circuits, indicating that the traditional formula does not adequately describe the behavior of electric potential in such contexts.

PREREQUISITES
  • Understanding of electric potential and its mathematical representation
  • Familiarity with Gauss's law and its implications in electrostatics
  • Knowledge of circuit theory and voltage concepts
  • Basic grasp of charge distribution in conductors
NEXT STEPS
  • Study the concept of continuous charge distributions in electrostatics
  • Learn about the application of Gauss's law in complex circuits
  • Explore the differences between point charges and distributed charges in electric fields
  • Investigate advanced circuit analysis techniques, such as nodal and mesh analysis
USEFUL FOR

Physics students, electrical engineers, and anyone seeking to deepen their understanding of electric potential and its application in circuit theory.

eyeweyew
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TL;DR
Electric potential at a point equation for circuit and net charge
I reviewed some of the fundamental physics and I looked back at the equation for Electric potential at a point p:
$$V(p) = k \sum_{i} {\frac {q_i} {r_i}}$$
where

- p is the point at which the potential is evaluated;
- ri is the distance between point p and point i at which there is a nonzero charge;
- qi is the charge at point i

and I still find it's kind of contradicting with the simple circuit model such as the one below. Both point a and point b should be neutral with no net charge so their electric field is 0 and the voltage is flat on the graph according to Gauss law. I understand the electric potential of point b is ε higher than that of point a (i.e. V(b)-V(a)=ε) means it takes ε work to move a +1 test charge from point a to point b along the circuit.

But according to Electric potential formula at a point, should that also imply there are higher positive net charge concentration around point b than point a so how can they both neutral with no net charge? Does that mean the equation for Electric potential at a point does not apply in a circuit model but if so, why?

electric_circuit_voltage_plots-001.png

image reference: https://tikz.net/electric_circuit_voltage_plots/
 
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Is that formula supposed to be the voltage at a point or the voltage due to a point charge? Read the surrounding text carefully
 
Dale said:
Is that formula supposed to be the voltage at a point or the voltage due to a point charge? Read the surrounding text carefully
It is voltage at a point due to other point charges. I edited my post to clarify it. Thanks!
 
eyeweyew said:
It is voltage at a point due to other point charges. I edited my post to clarify it. Thanks!
So that formula doesn’t really apply. There are no solitary point charges in that circuit. There is a continuous distribution of surface charge along all the conductors. That distribution doesn’t have a nice closed form expression.
 

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