Electric Potential of a Circular Rod

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Homework Help Overview

The discussion revolves around calculating the electric potential of a circular rod, focusing on the challenges of integrating charge density and understanding the relationship between charge distribution and potential. Participants express uncertainty about the necessary parameters and methods for approaching the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need for charge density and how to express it in terms of dq. There is mention of integrating charge density to find potential, but concerns about setting up the integral correctly are raised. Some participants suggest using surface charge concepts and question the nature of electric potential as a scalar versus vector quantity.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the assumptions about charge density and potential. Some guidance has been offered regarding the integration process, but no consensus has been reached on a specific approach.

Contextual Notes

Participants note the absence of certain parameters, such as lambda, and express confusion regarding the definitions and relationships between quantities involved in the problem.

Zythyr
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http://img136.imageshack.us/img136/7548/44938265by3.jpg

Okay I am not sure how to do this problem without having lambda. I talked to my professor and he said I don't need lambda.

I know that finding the potential due to a continuous charge is

dV = (Kdq)/r

But in this case, I am not sure how to do it. What is dq?

Can someone please explain to me how do I approach doing this problem.
 
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Hmm. I haven't figured out how to do the problem with a simple trick, which it sounds like your professor made one in there.

What is the charge density really? Charge per unit length. You can get the charge density and then integrate like normal. Though the integral is not entirely trivial to set up correctly, so there probably is some kind of trick we are missing.
 
you need the surface charge. You should have something like dV=bda; where b=surface charge of the tube. from there you input it back into to find V=k/r. at least that is how I would approach the problem.
 
I am confused.
 
1. What is the distance of the point on the axis and any point on the ring. Is it different for different point?

2. Whether electric potential is a vector quantity or a scalar and how the two type of quantities are added?
 

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