Electric Potential Over Non-Uniform Rod

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SUMMARY

The discussion focuses on calculating the electric potential at point P1 due to a thin plastic rod with a nonuniform linear charge density defined as λ = cx, where c = 14.5 pC/m² and L = 18.0 cm. The user initially attempted to compute the potential using the formula v = kc ∫[x/(x+d)]dx but received an incorrect result of -0.17V. The error was attributed to an incorrect integration process, highlighting the importance of meticulous integration in electric potential calculations.

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Homework Statement


The thin plastic rod shown in the figure has length L = 18.0 cm and a nonuniform linear charge density λ = cx, where c = 14.5 pC/m2. With V = 0 at infinity, find the electric potential at point P1 on the axis, at distance d = 5.10 cm from one end.

Figure is attached.

Homework Equations


q= \lambda x \\<br /> \lambda = cx \\<br /> dv = (kdq)/r

The Attempt at a Solution


q= \lambda x \\ <br /> dq = \lambda dx \\ <br /> dq = cxdx

I figured you would just use
v =kc \int_{0}^{L}[x/(x+d)]dx
And plug in L, solving for V, in which I get -0.17V, which is flagged as incorrect.

Am I approaching this correctly or is there something I am missing?
 

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The setup for the integral looks okay. You'll have to show details of how you solved the integral.
 
This can be closed, I just integrated incorrectly.
 

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