Electric power = I2*R= (0)2*infinity = can be any thing for open circuit?

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In an open circuit, resistance is infinite, resulting in zero current and thus zero power consumption, as calculated by the formula power = I * V. Even though the equation power = I² * R suggests that power could be anything when I is zero and R is infinite, the actual power dissipated remains zero. As resistance increases, current decreases, but power remains zero because it is defined as the product of current and voltage. The discussion emphasizes that while I approaching zero could suggest variable power, in the case of an open circuit, power is definitively zero. Therefore, an open circuit does not generate heat or dissipate power.
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In an open circuit resistance is infinity and therefore current is zero.(voltage 220V)
power=iv=0*220=0 watt
power=I2*R=(0)2*infinity=can be any thing (V=IR)
so,is power consumed zero or any thing?
 
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A resistor dissipates power in the form of heat (eg it gets warm or even hot). Would an open circuit get hot?
 
power=I2*R

Consider what happens as R approaches infinity and I approaches zero. Let's say you start with some value of R and then keep doubling it. At each step the current halves but the power changes by how much ? Work it out.
 
Here the current does not tend to zero but is exactly 0. Hence, 0*R where R tends to infinity is exactly zero, not just any value. So power dissipated must be zero. if i would have tend to zero, i.e, went very near zero then i*Rwould have taken any value..
 

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