Electrical Potential Energy Problem

AI Thread Summary
In the electrical potential energy problem, a metal sphere loses 10^13 electrons to another initially uncharged sphere, resulting in a potential energy of 7.2x10^-2 Joules. The charge of the first sphere is calculated by multiplying the number of electrons by the elementary charge, 1.60x10^-19 Coulombs. The user struggles with the formula involving the Coulomb constant and the distance between the spheres, initially using the same charge for both. A suggestion is made to assume the first sphere was neutral before losing electrons and to convert the charge to Coulombs for both spheres. Following this advice leads to a successful resolution of the problem.
Embermage
Messages
7
Reaction score
0
Hello,

I've been trying and trying to do this problem for quite a while now, and I can't seem to get an answer which agrees with the book.

In a charging process, 10^13 electrons are removed from a metal sphere and placed on a second sphere that is initially uncharged. Then the electrical potential energy associated with the two spheres is found to be 7.2x10^-2 Joules. What is the distance between the two spheres?

I figured that one metal sphere would then end up with a charge of 10^13 electrons (so I multiplied that by 1.60x10^-19 to get the charge of all the electrons in the sphere). But there is no charge given for the second sphere! I was using the equation:

(q1*q1/r)Coloumb Constant (8.99*10^9) = Energy

Nothing seems to work. Even using the same value for q1 and q1 doesn't produce the correct answer, which the book feels is 0.32 meters.

I'm stuck... thanks so much for any help!
 
Physics news on Phys.org
Try making the assumption that the sphere that lost the electrons was initially neutral in charge. Don't forget to convert electrons to coloumbs twice, once for each charge!

cookiemonster
 
Thank you very much... it worked like a charm.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top