Electrical power of a lightbulb

AI Thread Summary
When two identical light bulbs are connected to a battery, their electrical power differs based on the configuration. In series, the total resistance is 2R, while in parallel, the equivalent resistance is R/2. The power ratio of bulbs in series to those in parallel is calculated using the formula P = V^2/R. This results in a power ratio of 1:4, indicating that bulbs in parallel consume more power. Understanding the equivalent resistance in parallel circuits is crucial for accurate calculations.
Firye Stanly
Messages
4
Reaction score
0

Homework Statement


Two identical light bulbs are connected to the ends of the battery. In the first case they are connected in series and in the second they are connected in parallel mode. What is the ratio of the electrical power of light bulbs connected as mentioned?

Homework Equations


##P=I^2R##
##P=\frac{V^2}{R}##

The Attempt at a Solution


Since the voltage is the same and i take a light bulb to be a resistor shouldn't it just be ##R_1/R_2##? It somehow should be 1/4 but i don't get how. Total resistance in the first case is ##2R## and in the second is ##2/R## right?
 
Physics news on Phys.org
In the second case, total resistance is not 2/R. What is the formula for equivalent resistance of two parallel resistors?
 
cnh1995 said:
In the second case, total resistance is not 2/R. What is the formula for equivalent resistance of two parallel resistors?
Parallel resistors ##1/R_t = 1/R+1/R## so its ##R/2## so its ##1/4## oh thanks!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top