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Electrical supply system

  1. May 5, 2016 #1
    1. The problem statement, all variables and given/known data
    FIGURE 3 shows part of an electrical supply system.

    Draw the impedance diagrams reducing to a single impedance.

    Calculate the fault MVA levels in each unit for a fault on the left 3.3 kV bus with the bus section
    switch B open and A closed. Use a base MVA of 10 and show
    the fault MVA levels on a diagram.

    Comment on the result and suggest a method of improving the system to limit the fault MVA through T1 to approximately 5 × FL current. (It is not necessary to recalculate.)

    2. Relevant equations


    3. The attempt at a solution
    The fault MVA and pu impedances
    [tex]G_1 and G_2\text{fault MVA} = \frac{16}{0.8}=20MVA[/tex]
    [tex]G_1 and G_2\text{ pu impedance} = \frac{10}{20}\frac{20}{100}=0.1pu[/tex]
    [tex]G_3\text{fault MVA} = \frac{1.6}{0.8}=2MVA[/tex]
    [tex]G_3\text{ pu impedance} = \frac{10}{2}\frac{20}{100}=1pu[/tex]
    [tex]T_1,T_2and T_3\text{ pu impedance} = \frac{10}{10}\frac{5}{100}=0.05pu[/tex]
    So we need to work out the total impedance and fault current.
    [tex] T_2||T_3=0.025pu[/tex]
    [tex]G_3+T_2||T_3=1.025pu[/tex]
    [tex](G_3+T_2||T_3)||G_1||G_2=0.0477pu[/tex]
    [tex][(G_3+T_2||T_3)||G_1||G_2]+T_1=0.0977pu[/tex]
    So the fault MVA
    [tex]\frac{10}{0.0977}=102.4MVA[/tex]
    So the fault MVA through T1 is 102.4
    and through the rest
    [tex]\text{voltage MVA}(G_3+T_2||T_3)||G_1||G_2=102.4*0.0477=4.88MVA[/tex]
    Fault through G1 and G2
    [tex]\frac{4.88}{0.1}=48.88MVA[/tex]
    Fault through G3+T2||T3
    [tex]\frac{4.88}{1.025}=4.76[/tex]
    [tex]\text{voltage MVA G3}=4.76*1=4.76MVA[/tex]
    voltage MVA over T2||T3
    [tex]=0.025*4.76=0.119MVA[/tex]
    Fault through T2 and T3
    [tex]\frac{0.110}{0.05}=2.38MVA[/tex]

    I think this is correct.
    The part I am struggling with is
    "Comment on the result and suggest a method of improving the system to limit the fault MVA through T1 to approximately 5 × FL current. (It is not necessary to recalculate.)"

    Any help would be appreciated.
    Thanks
     

    Attached Files:

  2. jcsd
  3. May 10, 2016 #2
    Thanks for the post! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
     
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