Electricity - Resistance problem

AI Thread Summary
To calculate the resistance of a 240 W television operating for 4 hours daily, the energy consumed is 3,456,000 J. The user is unsure how to proceed with the calculations, noting the need to find either current or voltage first. They recognize the relationship between power, voltage, and current but feel stuck due to limited information. The discussion emphasizes the importance of understanding basic electrical equations to derive the necessary values. Clarifying the characteristics of household electricity in Canada could aid in solving the problem.
gvhunting
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Homework Statement



A 240 W television operates for 4.0 h a day in a typical Canadian home.
Calculate the resistance of the television.

Homework Equations



1) I = Q/∆ t 2) E = QxV 3) P = (Q x V)/ ∆t 4) P = I^2 x R
5) P = V^2/R 6) P = I x V 7) V = W/Q 8) V = E/Q
9) Q = I x ∆t 10) R = V/I


The Attempt at a Solution



Given:

P = 240 W
∆t = 4 h = 14 400 s
R = ?

E = P x ∆t
= 240 W x 14 400 s
= 3 456 000 J

I have done many practice problems but none such as this. I do not know where to go from here. There are many equations and I understand the most logical step next would be to either find the current or voltage and then using that value and Power to find the resistance. Or I can also find the value of Q and then using that and Power find either the current or voltage but not many values are given to do that.

Please help, I have been at this question for quite a while now, going around in circles.
 
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gvhunting said:

Homework Statement



A 240 W television operates for 4.0 h a day in a typical Canadian home.
Calculate the resistance of the television.

Homework Equations



1) I = Q/∆ t 2) E = QxV 3) P = (Q x V)/ ∆t 4) P = I^2 x R
5) P = V^2/R 6) P = I x V 7) V = W/Q 8) V = E/Q
9) Q = I x ∆t 10) R = V/I


The Attempt at a Solution



Given:

P = 240 W
∆t = 4 h = 14 400 s
R = ?

E = P x ∆t
= 240 W x 14 400 s
= 3 456 000 J

I have done many practice problems but none such as this. I do not know where to go from here. There are many equations and I understand the most logical step next would be to either find the current or voltage and then using that value and Power to find the resistance. Or I can also find the value of Q and then using that and Power find either the current or voltage but not many values are given to do that.

Please help, I have been at this question for quite a while now, going around in circles.
Hi gvhunting, Welcome to Physics Forums.

How is power related to voltage and current? How about resistance? What are the common characteristics of the electricity supplied to homes in Canada?
 
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