Electrodynamics- energy required for 2 charges approaching

AI Thread Summary
In the discussion, the user seeks clarification on calculating the work done when two charges approach each other, specifically using the formula W=q(Vf-Vi). They express confusion about why one charge is designated as q1 and the other as q2, and why the result remains consistent regardless of which charge is kept stationary. The conversation emphasizes that the choice of which charge to hold constant is arbitrary and does not affect the outcome of the calculation. The underlying principle is that electric potential energy changes are independent of the reference charge. Understanding this concept simplifies problem-solving in electrodynamics.
Mokha75
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Hi guys,

I have a quick q about solving questions where there are two charges q1 and q2 approaching each other (in this textbook problem it is from 0.1 m to 0.01m). I understand that you have to keep one of the charges stationary and use the formula:

W=q(Vf-Vi)
= q1[ (k*q2)/r2 - (k*q2) /r1]

where r2= 0.01m and r1 = 0.01m

however, I don't understand this conceptually, why are we plugging one of the charges in for q1 and how come we get the same answer regardless of which charge we decide to keep constant.

Hope that makes sense.

Thanks in advance!
 
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It's for convinience make s the problem easy to solve.
As such it is your choice to set the point of reference.
 
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nope
 
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